Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 255: 35

Answer

The force on the deltoid muscle is about 1600N

Work Step by Step

We sum the torques about the shoulder joint to find the force on the deltoid muscle. Therefore; $(+ \circlearrowleft) \sum \tau=0$ $F_M*\sin15^{\circ}*.12m-mg*.24m-8.5kg*g*.52m=0$ $F_M=\frac{mg*.24m+8.5kg*g*.52m}{\sin15^{\circ}*.12m}$ $F_M=\frac{3.3kg*9.8m/s^2*.24m+8.5kg*9.8m/s^2*.52m}{\sin15^{\circ}*.12m}$ $F_M\approx1600N$ The force on the deltoid muscle is about 1600N.
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