Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 255: 33

Answer

$F_V=2.40w$

Work Step by Step

$\sum\tau=0$ $(0.48m)\sin(12.0^o)F_M-(0.72m)\sin(45^o)(w_H)-(0.48m)\sin(45^o)(w_A)-(0.36m)\sin(45^o)(w_T)=0$ $F_M=1.98w$ $F_{Vy}=F_M\sin(33^o)+w_H+w_A+w_T=1.73w$ $F_{Vx}=F_M\cos(33^o)=1.66w$ $F_V=\sqrt{F_{Vy}^2+F_{Vx}^2}=2.40w$
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