Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 255: 32

Answer

The force required from the extensor muscle is about 970N

Work Step by Step

We sum the torques about the elbow joint to solve for the force required from the extensor muscle,$F_M$. Therefore; $(+ \circlearrowleft) \sum \tau=0$ $F_M*0.025m-2.3kg*g*.12m-7.3kg*g*.30m=0$ $F_M=(2.3kg*g*.12m+7.3kg*g*.30m)/(0.025m)$ $F_M=(2.3kg*9.8m/s^2*.12m+7.3kg*9.8m/s^2*.30m)/(0.025m)$ $F_M\approx970N$ The force required from the extensor muscle is about 970N.
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