Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - Problems - Page 255: 31

Answer

The person could hold a mass of 7.0kg

Work Step by Step

We sum the torques about the elbow joint to solve for the mass the person can hold. Therefore; $(+ \circlearrowleft) \sum \tau=0$ $.060m*450N-0.15m*2.0kg*g-.35m*5.0kg*g=0$ $m=\frac{.060m*450N-.15m*2.0kg*g}{.35m*g}$ $m=\frac{.060m*450N-.15m*2.0kg*9.8m/s^2}{.35m*9.8m/s^2}$ $m=7.0kg$ Therefore, the person could hold a mass of 7.0kg.
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