#### Answer

Choice E.

#### Work Step by Step

Consider the point just below the woman’s foot.
Three forces are acting: the woman’s weight pushing downward, the tension T in the wire pulling up and to the left along the direction of the wire on the left, and the tension T in the wire pulling up and to the right along the direction of the wire on the right.
Assume that the rope on the right is directed at an angle of $\theta$ above the horizontal. Applying Newton’s second law to this equilibrium case, it can be shown that her weight W is balanced by the 2 vertical forces working together: $W = 2 T sin \theta$.
The angle is small, so the sine of the angle is very small. We see that the tension T is many times greater than the weight, W.