Answer
a) See image
b) $F_G=65N$
$F_T=4.3N$
$F_B=69N$
c) $\sum\tau=140Nm$
Work Step by Step
a) See image
The support slot exerts both a downward and upward force on the beam to prevent it from rotating.
b) $\sum F_y=F_B-F_T-F_G=0N$
$F_G=65N$
$F_B=65N+F_T$
$\sum \tau_{CoM}=F_T(16.07cm)\cos(\theta_1)-F_B(14.08cm)\cos(\theta_2)=0$
$F_T(16.07cm)\cos(\arctan(\frac{1.5cm}{16cm}))-F_B(14.08cm)\cos(\arctan(\frac{1.5cm}{14cm}))=0$
$F_T=4.3N$
$F_B=69N$
c) $F_T$ exerts no torque
$\sum\tau=(69N)(\cos(\arctan(\frac{1.5}{2})))(\sqrt{1.5^2+2^2})=140Nm$