Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - General Problems - Page 259: 80

Answer

a) See image b) $F_G=65N$ $F_T=4.3N$ $F_B=69N$ c) $\sum\tau=140Nm$

Work Step by Step

a) See image The support slot exerts both a downward and upward force on the beam to prevent it from rotating. b) $\sum F_y=F_B-F_T-F_G=0N$ $F_G=65N$ $F_B=65N+F_T$ $\sum \tau_{CoM}=F_T(16.07cm)\cos(\theta_1)-F_B(14.08cm)\cos(\theta_2)=0$ $F_T(16.07cm)\cos(\arctan(\frac{1.5cm}{16cm}))-F_B(14.08cm)\cos(\arctan(\frac{1.5cm}{14cm}))=0$ $F_T=4.3N$ $F_B=69N$ c) $F_T$ exerts no torque $\sum\tau=(69N)(\cos(\arctan(\frac{1.5}{2})))(\sqrt{1.5^2+2^2})=140Nm$
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