Answer
$F_P=2100N$
Mechanical advantage is $1.3$
Work Step by Step
For the vertical section of the rope, $F_T=F_G$
$0.25m$
$cos(\theta)=\frac{3m}{3.25m}$
$\theta=22.6^o$
$F_x=F_T\sin(\theta)=mg\sin(\theta)=1055N$
$F_P=2100N$
$mg=2744N$
Mechanical advantage is $1.3$