Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 9 - Static Equilibrium; Elasticity and Fracture - General Problems - Page 258: 73

Answer

$F_P=2100N$ Mechanical advantage is $1.3$

Work Step by Step

For the vertical section of the rope, $F_T=F_G$ $0.25m$ $cos(\theta)=\frac{3m}{3.25m}$ $\theta=22.6^o$ $F_x=F_T\sin(\theta)=mg\sin(\theta)=1055N$ $F_P=2100N$ $mg=2744N$ Mechanical advantage is $1.3$
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