Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems - Page 226: 74

Answer

$-0.773\frac{rad}{s}$

Work Step by Step

$m=65kg$ $r=5.5m$ $I=1850kgm^2$ $\omega_i=0$ $\sum L=0$ $v_p=4.0\frac{m}{s}$ $L_t=-L_p$ $I_t\omega_t=-I_p\omega_p$ $I_t\omega_t=-(mr^2)(\frac{v}{r})$ $\omega_t=-\frac{mrv}{I_t}$ $\omega_t=-\frac{(65kg)(5.5m)(4.0\frac{m}{s})}{1850kgm^2}=-0.773\frac{rad}{s}$
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