Answer
$-0.773\frac{rad}{s}$
Work Step by Step
$m=65kg$
$r=5.5m$
$I=1850kgm^2$
$\omega_i=0$
$\sum L=0$
$v_p=4.0\frac{m}{s}$
$L_t=-L_p$
$I_t\omega_t=-I_p\omega_p$
$I_t\omega_t=-(mr^2)(\frac{v}{r})$
$\omega_t=-\frac{mrv}{I_t}$
$\omega_t=-\frac{(65kg)(5.5m)(4.0\frac{m}{s})}{1850kgm^2}=-0.773\frac{rad}{s}$