Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems: 60

Answer

$5.12 \frac{kg \cdot m^2}{s}$.

Work Step by Step

Find the angular momentum using equation 8–18. $$L = I \omega = MR^2 \omega = (0.270 kg)(1.35m)^2(10.4 \frac{rad}{s})=5.12 \frac{kg \cdot m^2}{s}$$
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