Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems - Page 225: 53

Answer

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Work Step by Step

a. Treat the Earth as a uniform sphere. The angular frequency is $2 \pi$ radians per day. $$KE=\frac{1}{2}I\omega^2=\frac{1}{2}\frac{2}{5}MR_{Earth}^2(\frac{2\pi rad}{86400s})^2=2.6\times10^{29}J$$ b. Treat the Earth as a point mass. The angular frequency is one revolution per year. $$KE=\frac{1}{2}I\omega^2=\frac{1}{2}MR_{sun-Earth}^2(\frac{2\pi rad}{3.15\times10^7s})^2=2.7\times10^{33}J$$
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