Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems: 50

Answer

$1.36 \times 10^4 J$

Work Step by Step

The energy required equals the rotor’s final rotational kinetic energy. The final rotational speed is 8750 rpm = 916.3 rad/s. $$KE_{rot}=\frac{1}{2}I \omega^2 \approx 1.36 \times 10^4 J$$
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