Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems: 6

Answer

$9.3 \times 10^{-2}m$.

Work Step by Step

Each time the ball makes one revolution, it travels a distance $\pi D$ along the floor. $$12.0 rev\frac{\pi D \, meters}{1 rev}=3.5 \, m$$ Solve for $D \approx 9.3 \times 10^{-2}\,m $.
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