Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems: 16

Answer

$$\frac{\omega_1}{\omega_2} = \frac{R_2}{R_1} $$

Work Step by Step

The tangential speed of the turntable equals the tangential speed of the roller because there is no slipping between the surfaces. $$v_1=v_2$$ $$\omega_1 R_1=\omega_2 R_2$$ $$\frac{\omega_1}{\omega_2} = \frac{R_2}{R_1} $$
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