Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - General Problems - Page 227: 86

Answer

The minimum torque that will make the tire slip is $\tau = 570~m\cdot N$

Work Step by Step

The tires will not slip as long as the force $F$ between the tires and the road is less than the maximum possible force of static friction. To find the minimum force $F$ which can overcome friction, we can equate $F$ to the maximum possible force of static friction, $F = mg~\mu_s$ We can find the torque on one tire from this force. Note that the mass on each tire is 1/4th the total mass of the car. $\tau = r\cdot F = r\cdot mg~\mu_s$ $\tau = (0.33~m)(1080~kg/4)(9.80~m/s^2)(0.65)$ $\tau = 570~m\cdot N$ The minimum torque that will make the tire slip is $\tau = 570~m\cdot N$
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