Answer
The point at the top of the rim will have a speed of 4.50 m/s.
Work Step by Step
We can find the translational speed of the wheel at t = 2.25 s:
$v = at = (1.00~m/s^2)(2.25~s) = 2.25~m/s$
The point at the top of the rim will have a translational speed of $v$ plus the speed from the rotation of the wheel:
$speed = v + \omega r = 2v = (2)(2.25~m/s) = 4.50~m/s$
Therefore, the point at the top of the rim will have a speed of 4.50 m/s.