Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - General Problems - Page 227: 79

Answer

The point at the top of the rim will have a speed of 4.50 m/s.

Work Step by Step

We can find the translational speed of the wheel at t = 2.25 s: $v = at = (1.00~m/s^2)(2.25~s) = 2.25~m/s$ The point at the top of the rim will have a translational speed of $v$ plus the speed from the rotation of the wheel: $speed = v + \omega r = 2v = (2)(2.25~m/s) = 4.50~m/s$ Therefore, the point at the top of the rim will have a speed of 4.50 m/s.
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