Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 7 - Linear Momentum - Search and Learn - Page 197: 3

Answer

$\Delta x_s=1.5m$ (smaller block) $\Delta x_b=0.38m$ (bigger block)

Work Step by Step

1. Calculate final velocity of block of mass M given that all initial PE gets converted to KE $PE=Mg(0.35m)=3.5M$ $v_i=\sqrt{\frac{7M}{M}}=2.65m/s$ 2. Calculate horizontal velocities of 2 blocks after collision $M(2.65m/s)=M(v_b)+0.5M(v_s)$ $\frac{M(2.65m/s)^2}{2}=\frac{M(v_b)^2}{2}+\frac{0.5M(v_s)^2}{2}$ $v_s=3.53m/s$ $v_b=0.883m/s$ 3. Calculate time it takes for blocks to reach ground. $-0.95m=\frac{(-10m/s^2)t^2}{2}$ $t=0.436s$ 4. Calculate $\Delta x$ for each block $\Delta x_s=(3.53m/s)(0.436s)=1.5m$ $\Delta x_b=(0.883m/s)(0.436s)=0.38m$
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