Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 7 - Linear Momentum - Problems: 49

Answer

$6.5 \times 10^{-11}m$

Work Step by Step

Let the carbon atom be at the origin. Use equation 7-9a. $$x_{CM}=\frac{m_c x_c+m_O x_O}{ m_c +m_O }=\frac{(12u) (0) +(16u)(1.13 \times 10^{-10}m)}{12u+16u}=6.5 \times 10^{-11}m$$
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