Answer
1.5 $\frac{kg \cdot m}{s}$
Work Step by Step
To find the impulse, calculate the change in momentum. Let the positive direction be the direction of the paper’s motion.
$$\Delta p = m \Delta v = (0.50 kg)(3.0 \frac{m}{s}-0) =1.5 \frac{kg \cdot m}{s}$$