Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 7 - Linear Momentum - Problems - Page 192: 21

Answer

(a) $p_0 = 290~kg\cdot m/s$ toward the east (b) $Impulse = 290~kg\cdot m/s$ toward the west (c) $Impulse = 290~kg\cdot m/s$ toward the east (d) $F = 340 ~N$, which is directed toward the east

Work Step by Step

(a) $p_0 = mv_0 = (95~kg)(3.0~m/s) = 290~kg\cdot m/s$ The initial momentum is directed toward the east. (b) Since the fullback came to a stop, the impulse is equal in magnitude to $p_0$ but in the opposite direction. Therefore, $Impulse = 290~kg\cdot m/s$ to the west. (c) By Newton's third law, the impulse on the tackler must be equal in magnitude to the answer in part (b), but in the opposite direction. So, $Impulse = 290~kg\cdot m/s$ to the east (d) $Impulse = 290~kg\cdot m/s$ $F\cdot t = 290~kg\cdot m/s$ $F = \frac{290~kg\cdot m/s}{0.85~s}$ $F = 340 ~N$, which is directed to the east
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