## Physics: Principles with Applications (7th Edition)

The momentum in the horizontal direction will be conserved. Let the positive direction be the direction in which the bullet was originally moving. $$(0.022 kg)(240 m/s) + 0 = (0.022 kg)(150 m/s) + (2.0 kg)v$$ Solve for velocity v = 0.99 m/s, rounded to 2 significant figures.