Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 7 - Linear Momentum - General Problems - Page 195: 68

Answer

The final speed is 0.20 km/s in the original direction of asteroid A.

Work Step by Step

We can use conservation of momentum to solve this question: $m_A~v_A + m_B~v_B = (m_A+m_B)~v$ $(7.5\times 10^{12}~kg)(3.3~km/s)+(1.45\times 10^{13}~kg)(-1.4~km/s) = (7.5\times 10^{12}~kg +1.45\times 10^{13}~kg)~v$ $v = \frac{4.45\times 10^{12}~kg\cdot m/s}{2.2\times 10^{13}~kg}$ $v = 0.20~km/s$ The final speed is 0.20 km/s in the original direction of asteroid A.
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