Physics: Principles with Applications (7th Edition)

Published by Pearson

Chapter 6 - Work and Energy - Problems: 67

15.4 W.

Work Step by Step

The work done on the water is the change in PE, mgh. The power is the work done divided by time. $$P=\frac{W}{t}=\frac{mgh}{t}=\frac{(27.0 kg)(9.80\frac{m}{s^2})(3.50 m)}{60s}=15.4 W$$

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