Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems - Page 164: 4

Answer

(a) 1150 joules (b) 6000 joules

Work Step by Step

(a) Since the velocity is constant, the applied force is equal in magnitude to the frictional force. Therefore, Work = Force x Distance becomes $Work = F_f\times d$ Next, we find the amount of work using the above formula: $Work = F_f\times d$ $Work = (230)(5.0)$ $Work = 1150 ~joules$ (b) Since the velocity is constant, the applied force is equal in magnitude to the gravitational force. Therefore, Work = Force x Distance $Work = F_g\times d$ $Work = (1200)(5.0)$ $Work = 6000 ~joules$
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