Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems: 13

Answer

a. 2800 J. b. 2100 J.

Work Step by Step

The work done is the signed area under the force vs position graph. a. From 0 to 10.0 m, the shape is a trapezoid, with an area of $W_1 = (400 N)\frac{1}{2}(10 m + 4 m) = 2800 J$. b. From 10.0 to 15.0 m, the shape is also a trapezoid, but the force is negative. The work done is $W_2 = (-200 N)\frac{1}{2}(5 m + 2 m) = -700 J$. The net work from 0 to 15.0 m is 2100 J.
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