Answer
$2.79g$
Work Step by Step
$m=1.9\times10^{27}kg$
$r_{J}=7.1\times10^7m$
$T=35700s$
$g_J=G\frac{m_J}{r_J^2}=(6.67\times10^{-11}\frac{Nm^2}{kg^2})\frac{1.9\times10^{27}kg}{(7.1\times10^7m)^2}=25.1\frac{m}{s^2}$
$v=\frac{2\pi r}{T}=\frac{2\pi(7.1\times10^7m)}{35700s}=12500\frac{m}{s}$
$F_R=\frac{v^2}{r}=\frac{(12500\frac{m}{s})^2}{7.1\times10^7m}=2.20\frac{m}{s^2}$
$a_G=25.1\frac{m}{s^2}+2.20\frac{m}{s^2}=27.3\frac{m}{s^2}$
$\frac{27.3\frac{m}{s^2}}{9.8\frac{m}{s^2}}=2.79g$