Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems - Page 133: 20

Answer

28.12 m

Work Step by Step

For an unbanked curve, the static friction coefficient for rubber on wet concrete is 0.7. The static frictional force will be at its maximum if the car is just at the point of slipping. We find the radius of curvature using the following formula: $$\frac{mv^2}{r}=µ_s mg$$ Rearranging the above formula and solving: $$r=\frac{v^2}{µ_sg}=\frac{((50km/h)(\frac{1000m}{1km})(\frac{1h}{3600s}))^2}{(0.7)(9.8m/s^2)}=28.12m$$ So, the radius of the curvature of the unbanked curve is 28.12 m.
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