# Chapter 5 - Circular Motion; Gravitation - Problems: 5

13 m/s.

#### Work Step by Step

The net horizontal force, the tension, is the centripetal force that causes the circular motion. $$F_{net}=75 N = ma_R=\frac{mv^2}{r}=\frac{(0.55 kg)(v)^2}{1.3 m}$$ $$v=\sqrt{\frac{(75 N)(1.3 m)}{0.55 kg}} \approx 13 m/s$$ The answer is displayed to 2 significant figures.

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