# Chapter 5 - Circular Motion; Gravitation - Problems: 2

5.41g.

#### Work Step by Step

Use equation 5–1 to find the centripetal acceleration. $$a_R=\frac{v^2}{r}=\frac{(525 m/s)^2}{5200 m} \approx 53.0 \frac{m}{s^2}$$ This is (53.0/9.80) = 5.41g. The answer is rounded to 3 significant figures.

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