Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems: 1

Answer

a. $1.01 \frac{m}{s^2}$ b. 22.7 N

Work Step by Step

a. Use equation 5–1 to find the centripetal acceleration. $$a_R=\frac{v^2}{r}=\frac{(1.10 m/s)^2}{1.20 m} \approx 1.01 \frac{m}{s^2}$$ The answer is rounded to 3 significant figures. b. The net horizontal force is the centripetal force that causes the circular motion. $$F_{net}=ma_R=\frac{mv^2}{r}=\frac{(22.5 kg)(1.10 m/s)^2}{1.20 m} \approx 22.7 N$$ The answer is rounded to 3 significant figures.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.