# Chapter 5 - Circular Motion; Gravitation - Problems: 1

a. $1.01 \frac{m}{s^2}$ b. 22.7 N

#### Work Step by Step

a. Use equation 5–1 to find the centripetal acceleration. $$a_R=\frac{v^2}{r}=\frac{(1.10 m/s)^2}{1.20 m} \approx 1.01 \frac{m}{s^2}$$ The answer is rounded to 3 significant figures. b. The net horizontal force is the centripetal force that causes the circular motion. $$F_{net}=ma_R=\frac{mv^2}{r}=\frac{(22.5 kg)(1.10 m/s)^2}{1.20 m} \approx 22.7 N$$ The answer is rounded to 3 significant figures.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.