Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - General Problems: 80

Answer

$7.1\times10^3s$

Work Step by Step

The speed of an object in an orbit of radius $r$ around the Moon is given by $v=\sqrt{\frac{GM_{Moon}}{r}}$ and also $v=\frac{2\pi r}{T}$, where T is the period of the object in orbit. Equate the two expressions and solve for $T$. $$v=\sqrt{\frac{GM_{Moon}}{r}}=\frac{2\pi r}{T}$$ $$T=2\pi\sqrt{\frac{r^3}{GM_{Moon}}}=2\pi\sqrt{\frac{(R_{Moon}+100km)^3}{GM_{Moon}}}=2\pi\sqrt{\frac{(1.74\times10^6m+1\times10^5m)^3}{(6.67\times10^{-11}Nm^2/kg^2)(7.35\times10^{22}kg)}}$$ $$=7.1\times10^3s$$
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