Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - General Problems - Page 136: 74

Answer

a) $F_f=187N$ b) $F_f=112N$ on $8^o$ angle incline

Work Step by Step

a) $F_f=F_R=\frac{mv^2}{r}=\frac{(55kg)\big(44\frac{m}{s}\big)^2}{570m}=187N$ b) $F_R=F_{NX}+F_{SX}=\frac{mv^2}{r}$ $\frac{(55kg)\big(44\frac{m}{s}\big)^2}{570m}=(55kg)\big(9.8\frac{m}{s^2}\big)tan(8^o)+F_{SX}$ $F_{SX}=111N$ $F_S=\frac{F_{SX}}{\cos(8^o)}=112N$
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