Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 4 - Dynamics: Newton's Laws of Motion - Problems - Page 104: 51

Answer

The average retarding force is $1.20 \times 10^2 ~N$ opposing the direction of motion.

Work Step by Step

We can use kinematics to find the acceleration. $a = \frac{v^2-v_0^2}{2x} = \frac{0 - (10.0 ~m/s^2)}{(2)(25.0 ~m)} = -2.00 ~m/s^2$ The force causes a deceleration of $2.00 ~m/s^2$ $F = ma = (60.0 ~kg)(2.00 ~m/s^2) = 1.20 \times 10^2 ~N$ The average retarding force is $1.20 \times 10^2 ~N$ opposing the direction of motion.
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