Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 4 - Dynamics: Newton's Laws of Motion - Problems: 18

Answer

$0.435 \frac{m}{s^{2}}$ in the upward direction.

Work Step by Step

Apply Newton’s second law to the elevator. Choose up to be the positive direction. $$\Sigma F=F_t – mg = ma$$ $$a = \frac{ F_t-mg}{m} =\frac{21750 N-(2125 kg)(9.80 \frac{m}{s^{2}})}{2125 kg} \approx 0.435 \frac{m}{s^{2}}$$ The answer is rounded to 3 significant figures. The positive sign confirms that the acceleration is upward.
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