Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 4 - Dynamics: Newton's Laws of Motion - Problems - Page 101: 12

Answer

$1.84 \frac{m}{s^{2}}$.

Work Step by Step

Choose up to be the positive direction. Newton’s second law tells us the required net force in the vertical direction. $$\Sigma F=F_t – mg = ma$$ $$a = \frac{ F_t-mg}{m} =\frac{163 N-(14.0 kg)(9.80 \frac{m}{s^{2}})}{14.0 kg} \approx 1.84 \frac{m}{s^{2}}$$ The answer is rounded to 3 significant figures. It is positive so the acceleration is upward. 163 N exceeds the weight, so the bucket is being lowered vertically, but slowing down.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.