Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 4 - Dynamics: Newton's Laws of Motion - Problems - Page 101: 10

Answer

$1.3 \times 10^{4} N$.

Work Step by Step

Choose up to be the positive direction. Use Newton’s second law to find the required net force in the vertical direction. $$\Sigma F=F_t – mg = ma$$ $$F_t=m(g+a) = (1200 kg)(9.80 \frac{m}{s^{2}}+0.70 \frac{m}{s^{2}}) \approx 13000 N $$ The answer is rounded to 2 significant figures.
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