Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 32 - Elementary Particles - Problems - Page 944: 4

Answer

$2.1\times10^{-5}s$

Work Step by Step

The time for one revolution is the circumference divided by the protons’ speed. The “very high energy” protons travel at just under the speed of light. $$T=\frac{2\pi r}{v}=\frac{2 \pi (1.0\times10^3 m)}{3.00\times10^8m/s}$$ $$T=2.1\times10^{-5}s $$
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