Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 32 - Elementary Particles - Problems - Page 944: 12

Answer

41.1 MeV

Work Step by Step

The energy released is the difference in the mass energy between the initial particle(s) and the final particle(s). The energy released is positive if the initial particle(s) has/have more energy. $$E_{release}=m_{\Lambda^o}c^2- m_{n}c^2- m_{\pi^o}c^2$$ $$E_{release}=1115.7 MeV-939.6MeV-135.0MeV=41.1MeV$$
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