Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 31 - Nuclear Energy; Effects and Uses of Radiation - Questions - Page 909: 2

Answer

$^{22}_{11}Na + \;^{2}_{1}H\rightarrow\;^{20}_{10}Ne + \alpha$.

Work Step by Step

$$^{22}_{11}Na + \;^{2}_{1}H\rightarrow\;? + \alpha$$ Recall that $ \alpha$ is $^{4}_{2}He$. Conserve nucleon number: 22 + 2 = A + 4. We see that A = 20. Conserve charge: 11 + 1 = Z + 2. We see that Z = 10. $$^{22}_{11}Na + \;^{2}_{1}H\rightarrow\;^{20}_{10}Ne + \alpha$$
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