Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 31 - Nuclear Energy; Effects and Uses of Radiation - Problems - Page 912: 49

Answer

$9\times10^{16}e^-$

Work Step by Step

Find the number of electrons from the dose, the mass of the beef, and the energy per electron. $$(4.5\times10^3Gy)(\frac{J/kg}{Gy})(5\;kg)(\frac{MeV}{1.60\times10^{-13}J})(\frac{1\;e^-}{1.6\;MeV})$$ $$=8.78\times10^{16}e^-\approx 9\times10^{16}e^-$$
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