Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 31 - Nuclear Energy; Effects and Uses of Radiation - Problems - Page 912: 44

Answer

$3.9\times10^2counts/s$

Work Step by Step

The counting rate is $85\%$ of $35\%$ of the beta particles emitted per second (the activity). $$(0.035\times10^{-6}Ci)(\frac{3.7\times10^{10}decays/s}{1\;Ci})(\frac{1\;\beta}{decay})(0.35)(0.85)$$ $$=385.3\;counts/s\approx 3.9\times10^2counts/s$$
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