Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 31 - Nuclear Energy; Effects and Uses of Radiation - General Problems - Page 913: 68

Answer

$1.4\times10^3\frac{decays/s}{m^{2}}$

Work Step by Step

Use the surface area of a sphere, $4 \pi r^2$ and find the activity per square meter. $$\frac{Activity}{m^2}=\frac{2.0\times10^7Ci}{4\pi r^{2}_{Earth}}$$ $$=\frac{(2.0\times10^7Ci)(3.7\times10^{10}decays/s)}{4\pi (6.38\times10^6 m)^{2}}$$ $$=1.4\times10^3\frac{decays/s}{m^{2}}$$
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