Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 31 - Nuclear Energy; Effects and Uses of Radiation - General Problems - Page 913: 65

Answer

$8\times10^{12}J$.

Work Step by Step

Find the number of U-235 nuclei. $$(2.0\;kg) \frac{6.02\times10^{23}U_{238}}{0.238kg}(0.05\frac{U_{235}}{U_{238}})=2.53\times10^{23}$$ We are given the information in problems 18-20 that 200 MeV of energy is released per fission. Multiply 200 MeV by the number of fissions, which is the number of U-235 atoms. $$E=(200MeV)(2.53\times10^{23}) \frac{1.602\times10^{-13}J}{1MeV}\approx 8\times10^{12}J$$
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