Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 30 - Nuclear Physics and Radioactivity - Problems - Page 881: 4

Answer

a. 5.8 fm b. $\approx$ 29

Work Step by Step

Use equation 30–1. a. $$r=(1.2\times10^{-15}m)A^{1/3}=(1.2\times10^{-15}m)112^{1/3}=5.8 fm$$ b. $$r=(1.2\times10^{-15}m)A^{1/3} $$ $$A=(\frac{r}{1.2\times10^{-15}m })^{3} $$ $$A=(\frac{3.7\times10^{-15}m }{1.2\times10^{-15}m })^{3}\approx 29 $$
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