Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 30 - Nuclear Physics and Radioactivity - Problems - Page 881: 26

Answer

See asnwers.

Work Step by Step

Find the difference between the final masses, and the initial mass. a. $$\Delta m=\left( m(^{232}_{92}U)+ m(^{1}_{0}n)-m(^{233}_{92}U) \right) $$ $$ =\left(232.037156u+1.008665u-233.039636u \right)$$ $$ =0.006185u$$ The final mass is more than the initial mass, so the decay isn’t possible. b. $$\Delta m=\left( m(^{13}_{7}N)+ m(^{1}_{0}n)-m(^{14}_{7}N) \right) $$ $$ =\left(13.005739u+1.008665u-14.003074u \right) $$ $$ =0.011330u$$ The final mass is more than the initial mass, so the decay isn’t possible. c. $$\Delta m=\left( m(^{39}_{19}K)+ m(^{1}_{0}n)-m(^{40}_{19}K) \right) $$ $$ =\left(38.963706u+1.008665u-39.963998u \right) $$ $$ =0.008373u$$ The final mass is more than the initial mass, so the decay isn’t possible.
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