Answer
See answers.
Work Step by Step
a. See Example 30-4.
$^{7}_{3}Li$ has 3 protons and 4 neutrons. Calculate the binding energy using the masses of the components and the mass of the nucleus. See Appendix B.
$$E_{binding}=\left( 3m(^{1}_{1}H)+4m(^{1}_{0}n)-m(^{7}_{3}Li)\right)c^2$$
$$ =\left( 3(1.007825u)+4(1.008665u)-(7.016003u)\right)c^2\left( \frac{931.49MeV/c^2}{u}\right)$$
$$ =39.25MeV$$
Binding energy per nucleon is 39.2455MeV/7 nucleons = 5.607MeV/nucleon.
b. See Example 30-4.
$^{195}_{78}Pt$ has 78 protons and 117 neutrons. Calculate the binding energy using the masses of the components and the mass of the nucleus. See Appendix B.
$$E_{binding}=\left( 78m(^{1}_{1}H)+117m(^{1}_{0}n)-m(^{195}_{78}Pt)\right)c^2$$
$$ =\left( 78(1.007825u)+117(1.008665u)-(194.964792u)\right)c^2\left( \frac{931.49MeV/c^2}{u}\right)$$
$$ =1546MeV$$
Binding energy per nucleon is 1545.68MeV/195 nucleons = 7.927MeV/nucleon.