Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 3 - Kinematics in Two Dimensions; Vectors - Problems - Page 71: 45

Answer

5.31$^o$ west of south.

Work Step by Step

Call east the positive x direction and north the positive y direction. Let P denote the Plane, A the Air, and G the Ground. The pair “PG”, for example, represents the plane’s motion relative to the ground. $$ \vec{v_{PG}} = \vec{v_{PA}} + \vec{v_{AG}} $$ $$(0, V) = (688 cos \theta, 688 sin \theta) km/h + (90.0 cos 45 ^{\circ}, 90.0 sin 45 ^{\circ}) km/h$$ Equate the x-components on both sides to solve for the angle of 264.69$^o$, or approximately 5.31$^o$ west of south.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.