## Physics: Principles with Applications (7th Edition)

Let x= 0 and y = 0 where the shot put is launched, and let upward be the positive y direction. The projectile’s initial vertical velocity is $(14.4 m/s)(sin 34 ^{\circ})$. The vertical acceleration is $-9.8 \frac{m}{s^{2}}$, negative because it is directed downward. The final vertical position is -2.1 m. Use equation 2.11b to find the time of flight of 1.87 s. The other root, a negative time, is discarded. The horizontal distance covered is the constant horizontal velocity multiplied by the time. $$(14.4 m/s)(cos 34 ^{\circ})(1.87 s) = 22.3 m.$$