## Physics: Principles with Applications (7th Edition)

Let the ground be level, with upward as the positive direction. The initial y is 910 m, and the final y is 150 m. The initial vertical velocity is 0. The vertical acceleration is $-9.8 \frac{m}{s^{2}}$, negative because it is directed downward. Use equation 2.11b to solve for the time of 12.45 s. Calculate the horizontal displacement as the horizontal velocity multiplied by the time: (4.0 m/s)(12.45 s) = 49.8 m.