Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 3 - Kinematics in Two Dimensions; Vectors - Problems: 26


a. 12 s b. 50 m

Work Step by Step

Let the ground be level, with upward as the positive direction. The initial y is 910 m, and the final y is 150 m. The initial vertical velocity is 0. The vertical acceleration is $-9.8 \frac{m}{s^{2}}$, negative because it is directed downward. Use equation 2.11b to solve for the time of 12.45 s. Calculate the horizontal displacement as the horizontal velocity multiplied by the time: (4.0 m/s)(12.45 s) = 49.8 m.
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