## Physics: Principles with Applications (7th Edition)

Published by Pearson

# Chapter 3 - Kinematics in Two Dimensions; Vectors - Problems: 14

#### Answer

We assume that the angle is less than 90 degrees and can be in either quadrant I or II. If quadrant I: $V_{x} = V sin(\phi)$ and the y-component is $V_{y} = V cos(\phi)$. If quadrant II: $V_{x} = -V sin(\phi)$, and the y-component is $V_{y} = V cos(\phi)$.

#### Work Step by Step

If the angle is in the first quadrant, then the x-component is $V_{x} = V sin(\phi)$ and the y-component is $V_{y} = V cos(\phi)$. However, if the angle is in quadrant II, then the x-component is negative, $V_{x} = -V sin(\phi)$, and the y-component is $V_{y} = V cos(\phi)$.

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