## Physics: Principles with Applications (7th Edition)

A-C = (38.85 units, 51.66 units) R = 64.64; 53.06$^o$
Use equations 3.3a and 3.3b to find the x and y components. Vector C points at 270 degrees from the positive x-axis. Vector A = (38.85, 20.66) Vector C = (0, -31) Take the difference by subtracting corresponding components. A-C = (38.85 units, 51.66 units) $R = \sqrt {(38.85)^2+(51.66)^2} = 64.64$ $\theta=tan^{-1}(\frac{51.66}{38.85}) = 53.06^o$